![]() ![]() ![]() This means that, theoretically, the polarization of light can be rotated to any angle without loss of intensity, at least from this effect. Therefore the limit of (cos(pi/2n)) 2n as n goes to infinity is exp(0)=1. If you remember the definition of a derivative, you might see that this will be the same as derivative of pi*ln(cos(x)) at zero, if it exists. ![]() Now since exp is a continuous function, you can move the limit to the inside and find out where 2n*ln(cos(pi/2n)) goes. Intensity of reflected light depends on angle of incidence and refractive indices (Fresnel equations). For partially polarized light, return to the main text. This equation is valid for totally polarized light. (cos(pi/2n)) 2n = exp(ln((cos(pi/2n)) 2n)) = exp(2n*ln(cos(pi/2n))) Intensity of linear polarized light angle dependent. What we can measure relatively easily is the intensity of the light when viewed through a polarizing filter oriented at various angles. Another way to figure out what that value is, other than my first proposal is to see Malus law: This law states that the intensity of the polarized light transmitted through the analyzer varies as the square of the cosine of the angle between. So if you chain together n polarizers, each successive one at an angle of pi/2n with respect to the previous, you rotate the polarization of the light by a full pi/2, and the new intensity isĪs n increases, this settles down closer and closer to a particular value (its limit). For polarization, the new intensity is the old intensity multiplied by the square of the cosine of the angle between the new and old planes of polarization. ![]()
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